12y/6y^2=1

Solution for 12y/6y^2=1 equation:

12y/6y^2=1

We move all terms to the left:

12y/6y^2-(1)=0


Domain of the equation: 6y^2!=0

y^2!=0/6

y^2!=√0

y!=0

y∈R


We multiply all the terms by the denominator


12y-1*6y^2=0

Wy multiply elements

-6y^2+12y=0

a = -6; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-6)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-6}=\frac{-24}{-12}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-6}=\frac{0}{-12}
=0
$